Math, asked by adithyamaurya2p599xs, 5 months ago

why is integration of vdv is v²/2​

Answers

Answered by Anonymous
22

Step-by-step explanation:

Bcoz

The integration of X^n dx is X^n+1/n+1

therefore,

integration of vdv is v²/2

Answered by dudejavasu001
0

Answer: Because Integration is the anti-derivative. Therefore, differentiation of \frac{v^2}{2} with respect to v will give v.

Given: We are given that the integration of v dv is \frac{v^2}{2}

To Find: We have to give the reason why is it so.

Step-by-Step Explanation:

We know that integration is the inverse of differentiation. In this process, we are given the derivative and we find its primitive. Integration is also called as anti-differentiation.

Now, we claim that \frac{v^2}{2} is the anti derivative of v. This means that if we differentiate \frac{v^2}{2}, we will get v.

Differentiating \frac{v^2}{2} with respect to v:

\frac{d}{dv}(\frac{v^2}{2}) = 2\times \frac{v}{2} = v

So, the integration of v dv is \frac{v^2}{2}

To know more about Calculus, refer to the links below:

https://brainly.in/question/13142910

https://brainly.in/question/22836174

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