Question

why is Mg2+ smaller than its corresponding atom.
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Answer 1

$\large\underline\purple{\bold{Solution :- }}$

We know that,

Cations are smaller and anions are greater in size than their corresponding neutral atom.

In anions, as the extra electrons are included, more electron - electron repulsion takes place and thus increases the size.

In cations, as electrons are removed, the nucleus attracts the elecreons, which are fewer than before, more strongly.

Thus, the distance between the nucleus and the valence orbit decreases, hence the size of cation decreases.

$\sf \: Therefore, \: {Mg}^{ + 2} \: is \: smaller \: than \: Mg \: atom.$

Answer 2

Answer:

[tex]\large{\underline{\purple{\bold{Solution :- }}}[\tex]

We know that,

Cations are smaller and anions are greater in size than their corresponding neutral atom.

In anions, as the extra electrons are included, more electron - electron repulsion takes place and thus increases the size.

In cations, as electrons are removed, the nucleus attracts the elecreons, which are fewer than before, more strongly.

Thus, the distance between the nucleus and the valence orbit decreases, hence the size of cation decreases.

Therefore, Mg^+2is smaller than Mg atom.