why is naphthalene -2- sulphonic acid is the major product in sulphonation of napthelene at higher temperature in reaction
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Answer: Naphthalene-2-sulphonic acid is the major product of the reaction because it is more stable than naphthalene-1-sulphonic acid.
Explanation: Sulfonation is a chemical reaction in which a sulfonic acid group (-SO3H) is introduced into an organic compound. In the case of naphthalene, the sulfonation reaction can occur at two positions on the aromatic ring, either at the 1-position or the 2-position.
At higher temperatures, the sulphonation of naphthalene is typically carried out using concentrated sulfuric acid, which is a strong acid and a strong oxidizing agent. Under these conditions, the sulphonation reaction is very fast and can lead to the formation of both naphthalene-1-sulphonic acid and naphthalene-2-sulphonic acid.
However, naphthalene-2-sulphonic acid is the major product of the reaction because it is more stable than naphthalene-1-sulphonic acid. This is due to the fact that the sulfonic acid group is located at the 2-position, which is closer to one of the aromatic rings. The presence of this ring provides additional stabilization through resonance, which reduces the overall energy of the molecule and makes it more stable.
In contrast, naphthalene-1-sulphonic acid is less stable because the sulfonic acid group is located at the 1-position, which is further away from the aromatic ring. As a result, this position does not benefit from resonance stabilization to the same extent as the 2-position, making the molecule less stable overall. Therefore, naphthalene-2-sulphonic acid is the major product of the sulphonation reaction at higher temperatures.
Learn more about Sulphonic acid here- https://brainly.in/question/45369091
Learn more about Naphthalene here - https://brainly.in/question/6933163
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