Question

why is osmotic pressure of 1M NACL higher than 1M glucose solution?

Answer 1

NaCl = 58.5 [g mol-1], so you can know dissolved NaCl is 1 mol, but the number of "all moles of solutes" in water is 2 mol because NaCl ionize into Na+ and Cl－.

V = 1 [L]
n = 58.5g58.5gmol-1×258.5g58.5gmol-1×2 = 2 [mol]
R = 8.31×103 [Pa L K-1 mol-1]
T = (273 + 27) = 300 [K]

Substituting these values forΠV=nRTΠV=nRTthenΠ⋅1=2⋅(8.31×103)⋅300Π=5.0×106[Pa]Π⋅1=2⋅(8.31×103)⋅300Π=5.0×106[Pa]


The result of question is 50 times as high as atmospheric pressure (≈ 105 Pa). You will know osmotic pressure is very high.

By the way, NaCl can be all dissolved in this question because the solubility of NaCl is 35.9g/100g(water) at 25 ℃.

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Answer 2

Answer:

It is a colligative property NaCl dissociated in to 2 ions but glucose does not , So number if particles in 1M NaCl will be twice as much as in 1M glucose