Question

Why is ratio of equivalent resistance of series combination of n equal resistance to equivalent resistance in parallel combination of these n resistance?

Answer 1

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For n equal parallel resistances, it is R/n. So the ratio of the resistance of the series string to the parallel combination is n squared, where n is the number of resistors. Two identical resistors are first connected in series and then in parallel.

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Answer 2

Answer:

$\huge\mathtt \red{ \longmapsto\frac{V\left(R_{2}+R_{3}\right)}{R_{1}R_{2}+R_{1}R_{3}+R_{2}R_{3}}}[/$