Question

why is tan inverse (-x) = $\pi$/2-tan inverse (x)
but sin inverse (-x)= - sin inverse (x)

Answer 1

Answer:

Step-by-step explanation:

NOT TRUE

tan inverse of - x = - tan inverse of x

BUT

tan inverse of 1 / x =

= pi / 2 - tan inverse of x if x > 0

AND

tan inverse of 1 / x =

= - pi / 2 - tan inverse of x if x < 0