Chemistry, asked by akashojha9121, 1 year ago

Why is Li_{2}CO_{3} decomposed at a lower temperature whereas Na_{2}CO_{3} at higher temperature ?

Answers

Answered by phillipinestest
0

The decomposition of any carbonate salt depends upon the ease with which the base can attract CO_2 and the stability of the salt.

In general, if the base is a strong one it attracts the acidic CO_2 very easily whereas the weak base cannot attract the acidic oxide that easily.

Thus, NaOH attracts CO_2 forming more stable salt.

More stable the salt, more is the energy needed for its decomposition. This accounts for the fact that Na_2CO_3 decomposes at a higher temperature. If we take the case of Li_2CO_3, it is a product of the weak base LiOH and weak acidic acid.

Since, weak acid cannot attract CO_2 easily. As such the salt formed is not stable.

Thus, it decomposes at a lower temperature indicating that less energy is enough for its decomposition to lithium oxide and carbon dioxide.

Further the small size of the lithium ion facilitates the polarisation of electron cloud of the oxygen atom to which it is attached. Thus, Li-O bond becomes stronger and C-O bond becomes weaker. Thus lithium carbonate decomposes as - Li_2CO_3 \rightarrow Li_2O+CO_2

Answered by ayush4894
0
The decomposition of any carbonate salt depends upon the ease with which the base can attract CO_2CO2​ and the stability of the salt.

In general, if the base is a strong one it attracts the acidic CO_2CO2​ very easily whereas the weak base cannot attract the acidic oxide that easily.

Thus, NaOH attracts CO_2CO2​ forming more stable salt.

More stable the salt, more is the energy needed for its decomposition. This accounts for the fact that Na_2CO_3Na2​CO3​decomposes at a higher temperature. If we take the case of Li_2CO_3Li2​CO3​ , it is a product of the weak base LiOH and weak acidic acid.

Since, weak acid cannot attract CO_2CO2​ easily. As such the salt formed is not stable.

Thus, it decomposes at a lower temperature indicating that less energy is enough for its decomposition to lithium oxide and carbon dioxide.

Further the small size of the lithium ion facilitates the polarisation of electron cloud of the oxygen atom to which it is attached. Thus, Li-O bond becomes stronger and C-O bond becomes weaker. Thus lithium carbonate decomposes as - Li_2CO_3 \rightarrow Li_2O+CO_2Li2​CO3​→Li2​O+CO2​

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