Question

Why is
$\sqrt{2}$

irrational

a Decimal representation is non terminating
b Decimal representation is non recurring
c Decimal representation is neither terminating nor recurring
d Decimal value is approximately 1.41

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Answer 1

Answer:

Hence the quotient has non-terminating value in decimal places. Also, it is to be noted that the decimal digits in the quotients are non-repeating or non-recurring. Hence the decimal expansion of √2 is non – terminating non-recurring.

Answer 2

Step-by-step explanation:

$\large \sf \blue{option \: no \: (c)}$