why is the base of transistor connected to a low potential
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heya @user
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The base of a bipolar junction transistor, when it is biased, so that the current current flows through the emitter, then there will be a junction voltage above the emitter. Therefore, if any circuit is emitter on zero capacity, then the base will be in 0V + VB, which will usually be 0.65V
NOTE : for a small-signal silicon NPN transistor where the bias current is in its recommended operating range
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here is your answer
___________________________
The base of a bipolar junction transistor, when it is biased, so that the current current flows through the emitter, then there will be a junction voltage above the emitter. Therefore, if any circuit is emitter on zero capacity, then the base will be in 0V + VB, which will usually be 0.65V
NOTE : for a small-signal silicon NPN transistor where the bias current is in its recommended operating range
____________________________
HOPE HELPED
CHEERS ☺☺
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