Question

Why is the formation of lead (II) iodide precipitate favoured over that of the tetraiodo plumbate (II) complex ion in low concentrations of iodide?

Answer 1

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Answer 2

$\tt { \: }^{ \huge Pb } {2}^{ { \: }^{ { \: }^{ { \: }^{ { \: }^{ { \: }^{ \huge \bold+ } } } } } } \: \: \: + \: \: 4 { I}^{ - } \longrightarrow \: \: { \: }^{ \huge Pb I} {2}^{ { \: }^{ { \: }^{ { \: }^{ { \: }^{ { \: }^{ { \: }^{ - } } } } } } }$