Question

Why is the nature of roots 3x²-4√3x+4=0.

Answer 1

We can derive their nature by using the relationship between the discriminant and the roots

Discriminant=b^2-4ac

=(-4√3)^2-4(3)(4)

48-48=0

We have this relation that if discriminant is 0

The roots are equal and real

(This means that the above expression can be written as

A perfect square)--- this is extra but still..

Hope it helps....plsss mark me as brainliest

Answer 2

hey frnd......
here we know that
D =
$\sqrt{ {b}^{2} - 4ac} \\ {(4 \sqrt{3)} }^{2} - 4(3)(4) \\ 48 - 48 \\ 48$
here D is zer.. ie D=0
then the roots are real and equal.

HOPE THIS HELP YOU ☺☺❤❤❤