Chemistry, asked by samadrita10, 3 months ago

Why is the oxygen-nitrogen proportion of 1:4 in the air appropriate?

Answers

Answered by bhaveshroy21

0

Answer:

Answer

The vapour pressure of air over water is 10 atm.

The partial pressure of nitrogen =PN2=10079×10=7.9atm=7.9×760mmHg=6004 mm Hg

The partial pressure of oxygen PO2=10020×10=2.0atm=2.0×760mmHg=1520 mm Hg

According to Henry's law,

PN2=KH(N2)×XN2

XN2=KH(N2)PN2=6.51×1076004=9.22×10−5

XO2=KHO

Explanation:

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