Why is the p.v. curve for an adiabatic process steeper than that for an isothermal process? Explain formation of clouds at night altitude.
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Explanation:
For adiabatic process-
PVγ=constant
Differentiating above equation, we have
V γdP+P(γV γ−1dV)=0
⇒V γdP=−γPV γ−1 dV
⇒ dVdP=−γ VP
Hence the slope of adiabatic curve =−γ VP
For isothermal process-
PV=constant
Differentiating above equation, we have
VdP+PdV=0
⇒VdP=−PdV
⇒ dVdP=− VP
Hence the slope of isothermal curve =− VP
Therefore,
Slope of isothermal curve
Slope of adiabatic curve
= (− VP )(−γVP)=γ
As γ is always greater than 1, the slope of an adiabatic curve is greater than that of an isothermal curve by a factor of γ.
Hence the adiabatic curve is steeper than the isothermal curve, in both the processes of expansion and compression.
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