Why is the plasma membrane called a selectively permeable membrane?
Answers
Explanation:
The plasma membrane is called a selectively permeable membrane as it permits the movement of only certain molecules in and out of the cells. ... If plasma membrane ruptures or breaks down then molecules of some substances will freely move in and out of the cells.
Answer:
Why are we normally advised to take bland and nourishing
food when we are sick?
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Why are we normally advised to take bland and nourishing
Why are we normally advised to take bland and nourishing
Why are we normally advised to take bland and nourishing food when we are sick?
Let p(x) = 2x4 – 5x3 + 2x2 – x+ 2 firstly, factorise x2-3x+2.
Let p(x) = 2x4 – 5x3 + 2x2 – x+ 2 firstly, factorise x2-3x+2.Now, x2-3x+2 = x2-2x-x+2 [by splitting middle term]
Let p(x) = 2x4 – 5x3 + 2x2 – x+ 2 firstly, factorise x2-3x+2.Now, x2-3x+2 = x2-2x-x+2 [by splitting middle term]= x(x-2)-1 (x-2)= (x-1)(x-2)
Let p(x) = 2x4 – 5x3 + 2x2 – x+ 2 firstly, factorise x2-3x+2.Now, x2-3x+2 = x2-2x-x+2 [by splitting middle term]= x(x-2)-1 (x-2)= (x-1)(x-2)Hence, 0 of x2-3x+2 are land 2.
Let p(x) = 2x4 – 5x3 + 2x2 – x+ 2 firstly, factorise x2-3x+2.Now, x2-3x+2 = x2-2x-x+2 [by splitting middle term]= x(x-2)-1 (x-2)= (x-1)(x-2)Hence, 0 of x2-3x+2 are land 2.We have to prove that, 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2 i.e., to prove that p (1) =0 and p(2) =0
Let p(x) = 2x4 – 5x3 + 2x2 – x+ 2 firstly, factorise x2-3x+2.Now, x2-3x+2 = x2-2x-x+2 [by splitting middle term]= x(x-2)-1 (x-2)= (x-1)(x-2)Hence, 0 of x2-3x+2 are land 2.We have to prove that, 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2 i.e., to prove that p (1) =0 and p(2) =0Now, p(1) = 2(1)4 – 5(1)3 + 2(1)2 -1 + 2 =2-5+2-1+2=6-6=0
Let p(x) = 2x4 – 5x3 + 2x2 – x+ 2 firstly, factorise x2-3x+2.Now, x2-3x+2 = x2-2x-x+2 [by splitting middle term]= x(x-2)-1 (x-2)= (x-1)(x-2)Hence, 0 of x2-3x+2 are land 2.We have to prove that, 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2 i.e., to prove that p (1) =0 and p(2) =0Now, p(1) = 2(1)4 – 5(1)3 + 2(1)2 -1 + 2 =2-5+2-1+2=6-6=0and p(2) = 2(2)4 – 5(2)3 + 2(2)2 – 2 + 2 = 2x16-5x8+2x4+ 0 = 32 – 40 + 8 = 40 – 40 =0
Let p(x) = 2x4 – 5x3 + 2x2 – x+ 2 firstly, factorise x2-3x+2.Now, x2-3x+2 = x2-2x-x+2 [by splitting middle term]= x(x-2)-1 (x-2)= (x-1)(x-2)Hence, 0 of x2-3x+2 are land 2.We have to prove that, 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2 i.e., to prove that p (1) =0 and p(2) =0Now, p(1) = 2(1)4 – 5(1)3 + 2(1)2 -1 + 2 =2-5+2-1+2=6-6=0and p(2) = 2(2)4 – 5(2)3 + 2(2)2 – 2 + 2 = 2x16-5x8+2x4+ 0 = 32 – 40 + 8 = 40 – 40 =0Hence, p(x) is divisible by x2-3x+2.