Question

why is the standard enthalpy of formation of a compound has the same value as the standard enthalpy of the compound?​

Answer 1

$\fbox\pink{A}\fbox\blue{n}\fbox\purple{s}\fbox\green{w}\fbox\red{e}\fbox\orange{r}$

This equation essentially states that the standard enthalpy change of formation is equal to the sum of the standard enthalpies of formation of the products minus the sum of the standard enthalpies of formation of the reactants. and the standard enthalpy of formation values: ΔHfo[A] = 433 KJ/mol