Why is the temporal gauge $A_0=0$ so popular in discussions of non-perturbative effects?
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Hey mate ^_^
To single out the relevant degree of freedom in the infinite-dimensional space of the gluon fields, it is necessary to proceed to the Hamiltonian formulation of Yang-Mills theory....
This implies, of course, that the time component of the four-potential Aμ has to be gauged away, A0=0....
#Be Brainly❤️
To single out the relevant degree of freedom in the infinite-dimensional space of the gluon fields, it is necessary to proceed to the Hamiltonian formulation of Yang-Mills theory....
This implies, of course, that the time component of the four-potential Aμ has to be gauged away, A0=0....
#Be Brainly❤️
Answered by
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Hello mate here is your answer.
To single out the relevant degree of freedom in the infinite-dimensional space of the gluon fields, it is necessary to proceed to the Hamiltonian formulation of Yang-Mills theory. This implies, of course, that the time component of the four-potential AμAμ has to be gauged away, A0=0A0=0.
Hope it helps you.
To single out the relevant degree of freedom in the infinite-dimensional space of the gluon fields, it is necessary to proceed to the Hamiltonian formulation of Yang-Mills theory. This implies, of course, that the time component of the four-potential AμAμ has to be gauged away, A0=0A0=0.
Hope it helps you.
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