Why is the $\theta$ term of QCD violating charge and parity (CP) symmetries?
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Hello ❤
That's not violation. It's due to Seymour ( SYMMETRY ) .
=> violation comes from the epsilon tensor in the dual field strength
That's not violation. It's due to Seymour ( SYMMETRY ) .
=> violation comes from the epsilon tensor in the dual field strength
Answered by
0
Hello Friend..❤️❤️
The answer of u r question is..
Ans:✍️✍️✍️✍️✌️✍️✍️
This is due to symmetry not due to violation.
Thank you..⭐️⭐️⭐️
The answer of u r question is..
Ans:✍️✍️✍️✍️✌️✍️✍️
This is due to symmetry not due to violation.
Thank you..⭐️⭐️⭐️
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