Why is the total resistance of a parallel circuit always lower than the lowest resister in the circuit?
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Equivalent resistance of two resistance in parallel =
1/ R = 1/R1 + 1/R2
R = R1 * [R2 /(R1 + R2)]
The factor in the parentheses is less than 1. so R is lower than R1 or R2.
Adding a resistance in parallel means providing an extra path for current to flow. So net resistance is less, as more current flows.
1/ R = 1/R1 + 1/R2
R = R1 * [R2 /(R1 + R2)]
The factor in the parentheses is less than 1. so R is lower than R1 or R2.
Adding a resistance in parallel means providing an extra path for current to flow. So net resistance is less, as more current flows.
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