why is the transition $3p^53d^2 \to 3p^63d^1$ (hydrogen atom) forbidden?
Answers
Answered by
7
Héy Héllø!!
So, Thé ÃnSwer is --) What I was thinking is that in 3d subshell (l=2) we have ... (spin up and down) and if we move to 3p we will fill the last ... ·
#ThankYou
I hope It's help!! Follow me
Marks me as Brilliant.
So, Thé ÃnSwer is --) What I was thinking is that in 3d subshell (l=2) we have ... (spin up and down) and if we move to 3p we will fill the last ... ·
#ThankYou
I hope It's help!! Follow me
Marks me as Brilliant.
Answered by
3
Hey mate ^_^
This is because a half filled sub shell or completely filled sub shell is more stable that's why (3p6)(3d0)(3p6)(3d0) since p orbital is completely filled and also according to Bohr's/Bury Rule the sub shell with lower value ofn+ln+lwill be filled first.
#Be Brainly❤️
This is because a half filled sub shell or completely filled sub shell is more stable that's why (3p6)(3d0)(3p6)(3d0) since p orbital is completely filled and also according to Bohr's/Bury Rule the sub shell with lower value ofn+ln+lwill be filled first.
#Be Brainly❤️
Similar questions