Why is the vapour pressure of an aqueous solution of glucose lower than that of water?
Answers
Answered by
204
Hey there!!!
The vapour pressure of an aqueous solution of glucose lower than that of water.
It is because in glucose solution, the surface of liquid consists of both solute and solvent molecules, therefore, the fraction of surface covered by the solvent molecules gets reduced.
Hence, escaping tendency of solvent molecules into vapours also gets reduced, thus, vapour pressure of glucose solution decreases.
Hope it helps :)
The vapour pressure of an aqueous solution of glucose lower than that of water.
It is because in glucose solution, the surface of liquid consists of both solute and solvent molecules, therefore, the fraction of surface covered by the solvent molecules gets reduced.
Hence, escaping tendency of solvent molecules into vapours also gets reduced, thus, vapour pressure of glucose solution decreases.
Hope it helps :)
Answered by
122
Hi friend,
Your answer:
This can be explained by the use of Raoult's law which states that when a nonvolatile solute is dissolved in a solvent, it lowers the vapor pressure of the solvent because of the interactions between solvent and solute molecules.
Similarly, on adding glucose to water, the vapour pressure decreases.
Hence,the vapour pressure of an aqueous solution of glucose is lower than that of water.
Hope it helps!
Your answer:
This can be explained by the use of Raoult's law which states that when a nonvolatile solute is dissolved in a solvent, it lowers the vapor pressure of the solvent because of the interactions between solvent and solute molecules.
Similarly, on adding glucose to water, the vapour pressure decreases.
Hence,the vapour pressure of an aqueous solution of glucose is lower than that of water.
Hope it helps!
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