Why is this method wrong?
Question: The diagonals of the quadrilateral ABCD intersect each other at the point O such that AO/BO = CO/DO. Show that ABCD is a trapezium
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It is not wrong but according to your proofs it can also be a symmetrical quadrilateral like a rectangle u need to show the angles are not sum to 90°. this is my opinion but the method is half right.
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