Question

why is XeF6 not distorted pentagonal bipyramidal although its hybridisation is Sp³d³?​

Answer 1

Answer:

Hybridization=arounded atoms to central atom+1/2(valence e- of central atom -bonded e- )

SO,hybridization of XeF6=6+1/2(8–6) =6+1

i.e.6+1=(bonded e-) +(lonpair)

So,hybridization=7=sp3d3

Its hybridisation is sp3d3 however its geometry is capped or distorted octahedral(square bipyramidal) one and not pentagonal bipyramidal. The flourine atoms occupy the vertices of the octahedron and lone pairs keeps on moving in space to minimise repulsion, and hence distorting the octahedral geometry. You can read more about XeF6 and its structure here:Xenon hexafluorid

Explanation: