why it do (t-1s) in 3rd line of solution ???
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due to last second as per asked in ques
narendra0786nm:
whats happen in 5th line i didn’t understand??
whats happen in last2nd line i didn’t understand??
we put the value of s and s' from 3 and5
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St =u(1s) +at (1s) -1/2a(1s)2
St= u(1s) + a/2 (1s) {2t- 1s}
we taken a/2(1s) common....then..
=u (1s) + a/2(2t - 1s) (1s)...
hope u can understand it..
I have tried my best..
St= u(1s) + a/2 (1s) {2t- 1s}
we taken a/2(1s) common....then..
=u (1s) + a/2(2t - 1s) (1s)...
hope u can understand it..
I have tried my best..
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