Question

why it is 12v/12k = 1mA?​

Answer 1

Answer:

When a 12 V battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit. Find the value of the resistance of the resistor. A 12 V battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit.

Answer 2

Answer:

We know that for faithful amplification, VCE should not be less than 1V for silicon transistor.

∴      Max. voltage allowed across RC = 6 − 1 = 5 V

∴      Max. allowed collector current = 5 V/RC = 5 V/2.5 kΩ = 2 mA

 

Thus, the maximum collector current allowed during any part of the signal is 2 mA. If the collector current is allowed to rise above this value, VCE will fall below 1 V. Consequently, value of β will fall, resulting in unfaithful amplification.

(ii) During the negative peak of the signal, collector current can at the most be allowed to become zero. As the negative and positive half cycles of the signal are equal, therefore, the change in collector current due to these will also be equal but in opposite direction.

∴       Minimum zero signal collector current required = 2 mA/2 = 1 mA

Step-by-step explanation:

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