Chemistry, asked by london2023, 1 year ago

Why K4[Fe(CN)6] is a better cogulating agent than Ca3(PO4)2 ?and pls don't spam,its a humble request.

Answers

Answered by abhirajpathak9
1
K4[Fe(CN)6] is a better coagulating agent if you are considering precipitation of positive sols as the coordination entity will have a charge of 4- as compared to (PO4)2-

london2023: pls do correct me frnd.....I f I am wrong anywhere
london2023: Thnk u so much
abhirajpathak9: Yeah charge on PO4 will be -3, i missed that i guess
abhirajpathak9: see your concept is spot on but when we are comparing the coagulation powers we are comparing for 1:1 moles of the species
abhirajpathak9: for eg if you take 2M K4[Fe(CN6] and 0.5M (Ca3PO4)2 then obviously the coordination entity will have the higher coagulating power
london2023: Frnd...thnk u so much for explaining me the stuffs....but i'm still confused a little bit......I'm so sorry frnd for disturbing u from time to time....but would u mind explaining it once again?.....My apologies again.
abhirajpathak9: 1 mole of (PO4)3- and one mole of [Fe(CN)6]4- both will have same no of molecules but definitely the coordination entity will have a greater negative charge by one unit. We are comparing the coagulation property considering we have a equal no of all the entities. We are not considering the concentration of this species
london2023: okhhhhhh...now i completely got it...thnk u so much frnd.....just thanking u makes me feel low....cuz u seriously helprd me out thru this....I was stuck in this part since a long time...Thnk u so much frndf once again....god bless u
london2023: Bye and take care frnd
abhirajpathak9: :)
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