Question

Why magnification is taken negative for real images and positive for virtual images?

Answer 1

If image is real, it will be inverted which means height of image will be taken as negative. Also, the height of object is always positive.
Now as magnification = Height of image / Height of object.

Therefore, in case of real image,
Magnification = Height of image (-) / height of object (+)=Negative.
So, Magnification will be negative.
Similarly, if image is virtual, it will be erect.

Therefore, in case of virtual image,
Magnification = Height of image (+) / height of object (+)= Positive
So, Magnification will be positive.


i hope this will help you

if helpful then please select my answer as brainliest answer
and also follow me ♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Answer 2

If image is real, it will be inverted which means height of image will be taken as negative. Also, the height of object is always positive.

Now as magnification = Height of image / Height of object.

Therefore, in case of real image,

Magnification = Height of image (-) / height of object (+)=Negative.

So, Magnification will be negative.

Similarly, if image is virtual, it will be erect.

Therefore, in case of virtual image,

Magnification = Height of image (+) / height of object (+)= Positive

So, Magnification will be positive.

This is your answer