Chemistry, asked by dikshesh278, 1 year ago

Why mixture of ethanol and acetone shows positive deviation from raoult's law

Answers

Answered by Anonymous
20

Molecules of ethanol in pure state are hydrogen bonded. But when acetone is added to the ethanol, molecules of acetone get in between the molecules of ethanol and break some of the hydrogen bond, which weaken the intermolecular attractive forces resulting in increase in vapour pressure of mixture than ethanol in pure state.

Because of this mixture of ethanol and acetone shows positive deviation in vapour pressure from Raoult’s Law.

 \huge \bold \red{hope \: it \: helps \: u}

Answered by ItzAshleshaMane
2

Answer:

A mixture of ethanol and acetone shows positive deviation from Raoult's Law. Pure ethanol possesses hydrogen bonding. Introduction of acetone between the molecules of ethanol results in breaking of some of these hydrogen bonds. Due to weakening of interactions, the solution shows positive deviation from Raoult's law.

Explanation:

Hope it will help you..

Similar questions