Why must electrostatic field at the surface of a charged conductor be prependicuar to every point on it ?
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As , electric field Inside a conductor is always zero . The electric field lines of a forces exert lateral pressure on each other leads to explain of repulsion between like charges . This in order to stable spacing , the electric field lines are normal to the surface.
As , electric field Inside a conductor is always zero . The electric field lines of a forces exert lateral pressure on each other leads to explain of repulsion between like charges . This in order to stable spacing , the electric field lines are normal to the surface.
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HELLO !《BRAINLY HELPER》
The electric field is perpendicular to every point on the surface of a conductor because the surface of a conductor is necessarily a surface of constant potential, the electric field, which is −∇φ−∇φ, must be perpendicular to the surface at every point on the surface.
EXPLANATION
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As the potential, φφ, is a continuous function, and since E=0E=0 inside the conductor and since E=−∇φE=−∇φ I get that φ=0φ=0inside and on the surface (from continuity) of the conductor.
_______________________________
HOPE I HELPED YOU !
The electric field is perpendicular to every point on the surface of a conductor because the surface of a conductor is necessarily a surface of constant potential, the electric field, which is −∇φ−∇φ, must be perpendicular to the surface at every point on the surface.
EXPLANATION
〰〰〰〰〰〰
_______________________________
As the potential, φφ, is a continuous function, and since E=0E=0 inside the conductor and since E=−∇φE=−∇φ I get that φ=0φ=0inside and on the surface (from continuity) of the conductor.
_______________________________
HOPE I HELPED YOU !
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