Chemistry, asked by mrkchalil2748, 11 months ago

Why nacl2 does not exist by bond haber cycle?

Answers

Answered by ItsSpiderman44
7

Answer:

Because the formation of Na2+ is an unfavorable process due to the great amount of energy required to remove the 2nd electron from the Na atom (the 2nd electron would have to be removed from the core electrons of the Na atom). ... Because the Cl- anion is too large for there to be two of them attached to one Na+ ion.

Answered by abhi178
0

Why NaCl₂ doesn't exist by Born Haber cycle ?

Born Haber Cycle :

  • It is the method or process that allows to observe and analyze the energies of the chemical reactions.
  • It helps to describe the formation of solid ionic crystalline compound from its elements.
  • A/C  to it, net enthalpy of the formation of compound must be zero.

The compound, NaCl₂, which has two ions Na²⁺ and 2Cl⁻. Here, A large amount of energy is required to form Na²⁺ because ionisation enthalpy of Na⁺ is very high (Na⁺ is a stable form of Na, configuration of Na⁺ is 1s² , 2s² , 2p⁶ shows it needs very high amount of energy to remove further electrons.).

To support of Na²⁺ formation, there is much lower is provided by the formation of Cl⁻. so the net enthalpy can not be zero. Hence, NaCl₂ doesn't exist by Born Haber Cycle.

Also read similar questions : Born-Haber cycle of BaO crystal.

https://brainly.in/question/1093845

born haber cycle for BaCl2

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