Why Ni^2+ form tetrahedral complex with CO and square planar with CN?
Answers
Answered by
0
Answer:
* In presence of strong field CN- ions, all the electrons are paired up. The empty 4d, 3s and two 4p orbitals undergo dsp2 hybridization to make bonds with CN- ligands in square planar geometry. Thus [Ni(CN)4]2- is diamagnetic.
Explanation:
please mark me brainliest plz plz
Answered by
0
Why Ni^2+ form tetrahedral complex with CO and square planar with CN?
* In presence of strong field CN- ions, all the electrons are paired up. The empty 4d, 3s and two 4p orbitals undergo dsp2 hybridization to make bonds with CN- ligands in square planar geometry. Thus [Ni(CN)4]2- is diamagnetic.
Similar questions