Physics, asked by vijitharenjusre813, 1 year ago

why no cycle can have efficiency greater than carnot

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Answered by himanshutiwari2
0
No engine can have the efficiency more than a Carnot cycle according to Carnot theorem “Heat engines operating between a given constant temperature source and given temperature sink none has a higher efficiency than a reversible engine.
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Answered by Atkah
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Your answer is


Imagine any heat engine operating between two different temperatures. The operation of the engine must involve four fundamental strokes, two in which it exchanges most of the heat, and two in which it does most of the work.

Now, efficiency for an engine = work done/heat accepted. Suppose I keep the maximum-P-minimum-V and maximum-V-minimum-P endpoints of the cycle same, and then try to modify it keeping the work (area in the cycle) constant. If we derive the expression for heat accepted, we'll see that it is always more than the isothermal heat accepted. The adiabatic step in the Carnot cycle does the magic. Since ΔQ is zero only for adiabatic process, so it is the adiabatic process that minimizes the heat accepted, and hence, maximizes the efficiency.

This is not rigorous, but this is what we observe decreases the efficiency in practical engines like Sterling engine. The non-adiabatic heat term is always the culprit.

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