Why o has less ionisation enthalpy than n?
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Hey there,
IP increase as we move from left to right in a period, But O and N is an exception because=
1s²,2s²,2p⁴ is the electronic configuration of O.
1s²,2s²,2p³ is the electronic configuration of N.
====================================
If you will notice the last orbital O has 2p⁴ and N has 2p³. Since the maximum capacity of p orbital is 6. So 2p³ is a half filled orbital.
And according to stability
Full filled>Half filled>Randomly filled
Though O has more electrons in valence orbital but N is more stable because of having a half filled valence orbital and hence have more IP because IP is directly proportional to stability.
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
IP increase as we move from left to right in a period, But O and N is an exception because=
1s²,2s²,2p⁴ is the electronic configuration of O.
1s²,2s²,2p³ is the electronic configuration of N.
====================================
If you will notice the last orbital O has 2p⁴ and N has 2p³. Since the maximum capacity of p orbital is 6. So 2p³ is a half filled orbital.
And according to stability
Full filled>Half filled>Randomly filled
Though O has more electrons in valence orbital but N is more stable because of having a half filled valence orbital and hence have more IP because IP is directly proportional to stability.
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
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