why O-O bond length in H2O2 lesser in solid phase than in gaseous phase ???
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Answer:
Intermolecular interactions of solids are greater than intermolecular interaction in gases, So the bond length of O-O bond is less in solid-state, it leads to more lone pair -lone pair repulsions and bond angle is more in the solid-state as compared to the gaseous state
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Answer:
it's my thinking.......
Explanation:
The bond length is slightly greater than length of a single bond, due to repulsion between the lone pairs of oxygen atoms.
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