Question

Why path of a projectile is horizontal at the point of maximum height​

Answer 1

Explanation:

R.E.F image

y=Px−Qx2

we know that,

y=xtanθ−2U2cos2θgx2

So comparing,

P=tanθ

Q=2U2cos2θq

cosθ=P2+11

sinθ=P2+1P

U2=2θg(P2+1)

(i) Range =g2U2sinθcosθ

=2×g2θ×g(P2+1)×(P2+1)P

⇒P/Q

(iii) max height =2gU2sin2θ

Answer 2

Answer:

When the projectile reaches a vertical velocity of zero, this is the maximum height of the projectile and then gravity will take over and accelerate the object downward. The horizontal displacement of the projectile is called the range of the projectile, and depends on the initial velocity of the object.

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