why ratio of hydrogen to oxygen is 2:1 by volume when formed at cathode and anode
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Answered by
94
Because Water's chemical representation is H₂O. That means, each water molecule has 2 hydrogen atoms & 1 oxygen atom. When electricity passes through water, the H₂O molecule breaks up into 2 Hydrogen & 1 oxygen atoms. So their ratio is 2 : 1. As we see...
At Cathode:
H⁺ + 1e⁻ → [H]
H + H → 2H → H₂
At Anode:
4OH⁻ - 4e⁻ → 2H₂O + O₂
Therefore, the ratio of hydrogen to oxygen is 2:1 by volume when formed at cathode and anode.
I hope it helps you ^_^
At Cathode:
H⁺ + 1e⁻ → [H]
H + H → 2H → H₂
At Anode:
4OH⁻ - 4e⁻ → 2H₂O + O₂
Therefore, the ratio of hydrogen to oxygen is 2:1 by volume when formed at cathode and anode.
I hope it helps you ^_^
Answered by
14
Answer:
2:1
Explanation:
Water contains two atoms of hydrogen and one atom of oxygen. Hence the volume of hydrogen and oxygen in water becomes 2:1.
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