Why resonance doesn't operate in CH2=CH–COOH ?
No spamming!!
Answers
Answered by
3
The following criteria allow you to evaluate proposed resonance structures:
1) Two resonance structures must involve the same set of atoms(don't add or lose atoms)
2) The structures must have the same net charge (don't add or lose electrons)
3) The atoms must be in the same position (the structures show different bonding schemes for a single set of atomic positions)
4) The number of electrons associated with an atom should not exceed the capacity of its valence orbitals (octet for 2nd-row elements)
5) Be sure that the formal charge on an atom reflects its nuclear charge, its half-interest in bonding pairs, and its possession of unshared pairs or odd electrons.
6) Preserve the maximum number of bonds. Relocate bonds, but don't lose bonds without having a very good reason for doing so (bond polarity maybe)
7) When polar forms are used to replace bonds, be sure that the charge distribution properly reflects relative electronegativity(energy mismatch).
8) If the structure reflects OMO/UMO mixing within the molecule, be sure the two orbitalsoverlap (s and p orbitals on the same atom are orthogonal).
This cases are not present in the structure
1) Two resonance structures must involve the same set of atoms(don't add or lose atoms)
2) The structures must have the same net charge (don't add or lose electrons)
3) The atoms must be in the same position (the structures show different bonding schemes for a single set of atomic positions)
4) The number of electrons associated with an atom should not exceed the capacity of its valence orbitals (octet for 2nd-row elements)
5) Be sure that the formal charge on an atom reflects its nuclear charge, its half-interest in bonding pairs, and its possession of unshared pairs or odd electrons.
6) Preserve the maximum number of bonds. Relocate bonds, but don't lose bonds without having a very good reason for doing so (bond polarity maybe)
7) When polar forms are used to replace bonds, be sure that the charge distribution properly reflects relative electronegativity(energy mismatch).
8) If the structure reflects OMO/UMO mixing within the molecule, be sure the two orbitalsoverlap (s and p orbitals on the same atom are orthogonal).
This cases are not present in the structure
moon1237879:
please mark it as brainliest answer
Answered by
1
Hi friend here is your answer
_____________________________
Resonance - - -
The delocalization of pi electron develops different electronic structure which are called resonating structure or canonical structure and this phenomenon is called resonance
_____________________________
Resonance take place when
1) pi electron move towards other pi electron eg benzene
2) pi electrons moves towards positive charge
3) Lone pair moves towards pi electron
(ALL SHOULD BE ALTERNATE POSITION)
So resonance is not possible in
CH2=CH–COOH
____________________________
Hope it helps you...............!!
#OO7
_____________________________
Resonance - - -
The delocalization of pi electron develops different electronic structure which are called resonating structure or canonical structure and this phenomenon is called resonance
_____________________________
Resonance take place when
1) pi electron move towards other pi electron eg benzene
2) pi electrons moves towards positive charge
3) Lone pair moves towards pi electron
(ALL SHOULD BE ALTERNATE POSITION)
So resonance is not possible in
CH2=CH–COOH
____________________________
Hope it helps you...............!!
#OO7
Similar questions