Chemistry, asked by rajeswari6782, 1 year ago

why resonance effect dominates over inductive effect in most of the cases?​

Answers

Answered by dhanashri69
10

In case of 2p-2p orbital overlapping, the resonance effect is dominating as you already know the order of resonance >hyperconjugation > inductive effect

But for halides….

Looking at halogens (dont get confused about case of fluorine now) they have what kind of overlapping? U r right!! It is 2p and 3p for cl, 2p-4p for Br and similarly 2p and 5p for I.

Therefore this is considered to be poor overlapping and weak chemical bonds which make resonance less effective (remember this point)

As resonance gets weak what dominates is the inductive (you are think of hyperconjugation??! Then you need to brush up your basic concepts again)

As inductive is now a dominant factor, carbon is less electronegative and thus develops partial positive charge and as nucleus of halogen pulls electron pair towards itself jt develops partial negative. Due to overlapping (scam) inductive effect dominates over the resonance effect in case of halogens.

I think you still must be perplexed about fluorine… we know that a fluorine atom is highly electronegative and so its nucleus will have high tendency of pulling opposite charges. So it becomes reluctant to donate electrons. resonance effect becomes less effective than inductive effect.

it may helpful for you


rajeswari6782: bt hv a doubt
rajeswari6782: inductive effect is weaker than resonance effect na?
rajeswari6782: as inductive effect is distance dependent and dies over 3/4 carbon
rajeswari6782: pls make that clr to me!
dhanashri69: ok l shall try it later
rajeswari6782: ya pls
dhanashri69: l should study that topic more
rajeswari6782: i too should
dhanashri69: yaa
rajeswari6782: hmm
Answered by animeshtiwari2902
2

In case of 2p-2p orbital overlapping, the resonance effect is dominating as you already know the order of resonance >hyperconjugation > inductive effect

But for halides….

Looking at halogens (dont get confused about case of fluorine now) they have what kind of overlapping? U r right!! It is 2p and 3p for cl, 2p-4p for Br and similarly 2p and 5p for I.

Therefore this is considered to be poor overlapping and weak chemical bonds which make resonance less effective (remember this point)

As resonance gets weak what dominates is the inductive (you are think of hyperconjugation??! Then you need to brush up your basic concepts again)

As inductive is now a dominant factor, carbon is less electronegative and thus develops partial positive charge and as nucleus of halogen pulls electron pair towards itself jt develops partial negative. Due to overlapping (scam) inductive effect dominates over the resonance effect in case of halogens.

I think you still must be perplexed about fluorine… we know that a fluorine atom is highly electronegative and so its nucleus will have high tendency of pulling opposite charges. So it becomes reluctant to donate electrons. resonance effect becomes less effective than inductive effect.

Hope this answer helps you

Please mark it as the brainliest


animeshtiwari2902: hiii
animeshtiwari2902: Please mark it as the brainliest answer
rajeswari6782: thanks bt don't waste ur tym answering my previous question
rajeswari6782: spam.....well i didn't expect this frm u
animeshtiwari2902: why
animeshtiwari2902: sorry for inconvenience
animeshtiwari2902: hiiii
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