Why second ionizationof copper is expected to be higher than that of zinc
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Because in the zinc electron is removed from 4s^2 configuration (which is in stable state) while in copper it is removed from 4s^1 configuration thus more energy is required for the removal of 4s^2 electron than that of 4s^1.
【MARK BRAINLIEST】
Answered by
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hey mate!!
_____________________________
→ ELECTRONIC CONFIGURATION OF
COPPER:- 1S2 2S2 2P6 3S2 3P6 4S1 3d10
ZINC :- 1S2 2S2 2P6 3S2 3P6 4S2 3d10
now,
as you know
2nd Iionisation means Removal of ion from unipositive atom.
→ electrons are always removed from outermost shell.
→ in case of copper 1st electron removed from 4s and then from 3d
→ to remove electron from 3d high energy required because it is fully filled.
→ in case of zinc, both electron is removed from 4s orbital.
NOTE:- AFTER REMOVING 2 ELECTRONS FROM ZINC IT'S OUTERMOST SHELL CHANGES FROM 4S TO 3d.
BUT , I.P OF REMOVING ELECTRONS FROM FULLY FILLED ORBITALS IS ALWAYS GREATER THEN CHANGE IN SHELL.
hope it helps!!
#Jaihind
_____________________________
→ ELECTRONIC CONFIGURATION OF
COPPER:- 1S2 2S2 2P6 3S2 3P6 4S1 3d10
ZINC :- 1S2 2S2 2P6 3S2 3P6 4S2 3d10
now,
as you know
2nd Iionisation means Removal of ion from unipositive atom.
→ electrons are always removed from outermost shell.
→ in case of copper 1st electron removed from 4s and then from 3d
→ to remove electron from 3d high energy required because it is fully filled.
→ in case of zinc, both electron is removed from 4s orbital.
NOTE:- AFTER REMOVING 2 ELECTRONS FROM ZINC IT'S OUTERMOST SHELL CHANGES FROM 4S TO 3d.
BUT , I.P OF REMOVING ELECTRONS FROM FULLY FILLED ORBITALS IS ALWAYS GREATER THEN CHANGE IN SHELL.
hope it helps!!
#Jaihind
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