Chemistry, asked by srushtitha27, 6 months ago

why secondary and tertiary alcohols be used with convented acid to obtain alkyl halides?​

Answers

Answered by Omkhatal
2

Explanation:

show that treating alcohols with HCl, HBr, or HI (which all fall under the catch-all term “HX” where X is a halide) results in the formation of alkyl halides. Summary:

summary alcohols converted to alkyl halides with strong acid hx conjugate acid of oh is oh2 which is good leaving group sn1 or sn2 mechanism

Table of Contents

Adding Acid To Alcohol Produces A Good Leaving Group (H2O)

Alkyl Halides From Methyl and Primary Alcohols via the SN2 Reaction

Alkyl Halides From Tertiary Alcohols Proceeds Through The SN1 Pathway

A Good Rule Of Thumb For Secondary Alcohols With HX: Assume SN1

Rearrangements In The Formation of Alkyl Halides From Alcohols

Rearrangement Example #1: Hydride Shift

Rearrangement Example #2: Alkyl Shift

Rearrangement Example #3: A Special Case of Alkyl Shift – Ring Expansion and Contraction

What Doesn’t Work?

Summary: Alkyl Halides From Alcohols

(Advanced) References and Further Reading

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