why (Sin)(cos)=1, (cos)(sec)=1, and (tan)(cot)=1 ???
bigansingh:
Instead of cos with sin there is cosec
Answers
Answered by
0
sinθ1−cosθ+tanθ1+cosθ
= sinθ(1+cosθ)(1−cosθ)(1+cosθ)+tanθ(1−cosθ)(1+cosθ)(1−cosθ)
= sinθ(1+cosθ)1−cos2θ+tanθ(1−cosθ)1−cos2θ
= sinθ(1+cosθ)sin2θ+sinθ(1−cosθ)cosθsin2θ
= 1+cosθsinθ+1−cosθcosθsinθ
= 1sinθ+cosθsinθ+1cosθsinθ−1sinθ
= cscθ+cotθ+secθcscθ−cscθ
= secθcscθ+cotθ
PLZ mark me as a BRAINLIST
= sinθ(1+cosθ)(1−cosθ)(1+cosθ)+tanθ(1−cosθ)(1+cosθ)(1−cosθ)
= sinθ(1+cosθ)1−cos2θ+tanθ(1−cosθ)1−cos2θ
= sinθ(1+cosθ)sin2θ+sinθ(1−cosθ)cosθsin2θ
= 1+cosθsinθ+1−cosθcosθsinθ
= 1sinθ+cosθsinθ+1cosθsinθ−1sinθ
= cscθ+cotθ+secθcscθ−cscθ
= secθcscθ+cotθ
PLZ mark me as a BRAINLIST
Answered by
0
=sin* cos
=sin*1/sin[cos=1/sin]
=1[sin will get cancelled]
=cos*sec
=cos*1/cos
=1
=tan*cot
=tan*1/tan
=1
HOPE THIS HELPS YOU BUDDY ✌️
IF YOU LIKE IT PLEASE MARK IT AS BRAINLIEST
=sin*1/sin[cos=1/sin]
=1[sin will get cancelled]
=cos*sec
=cos*1/cos
=1
=tan*cot
=tan*1/tan
=1
HOPE THIS HELPS YOU BUDDY ✌️
IF YOU LIKE IT PLEASE MARK IT AS BRAINLIEST
Similar questions