Question

why sin theta is p/h?​

Answer 1

sin A = p/h

sin A = p/hcosA=b/h

sin A = p/hcosA=b/htanA= p/b

sin A = p/hcosA=b/htanA= p/b cosA= h/p

sin A = p/hcosA=b/htanA= p/b cosA= h/psecA= h/b

sin A = p/hcosA=b/htanA= p/b cosA= h/psecA= h/bcotA= b/p

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Answer 2

well it is a trigonometric ratio,of sin/sine ie, in a right angle triangle of one the acute angles is equal to perpendicular (p) \hypotenuse