Question

why sodium carbonate is soluble but calcium carbonate is not

Answer 1

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Answer 2

Answer:

At a particular temperature, a 2.00Lflask at equilibrium contains 2.80×10−4 moles of N2, 2.5×10−5mole of O2and 2.00×10−2 mole of N2O. Calculate K at this temperature for the reaction, 2N2(g)+O2(g)→2N2O(g)

If [N2]=2×10−4M, [N2O]=0.200M and [O2]=0.00245M, does this represent a system at equilibrium.