Why the boiling point of 1-bromobutane is higher than 1-bromo-2-methylpropane?
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Answered by
13
1-bromobutane (n-butyl bromide) bp = 100°
among constitutional isomers, branched isomers
have a more compact shape,
decreased area of contact,
decreased van der Waals attractive forces between neighbors,while
have a more compact shape,
decreased area of contact,
decreased van der Waals attractive forces between neighbors,while
Answered by
11
Hey dear,
● Explanation -
- Branched chain alkanes have compact shape and weak van der Waals forces.
- Hence, boiling point decreases with increase in branching.
- As 1-bromo butane is straight chain alkane it has quite high boiling point.
- As 2-bromo-2-methyl propane is branched chain alkane its boiling point is lower.
Hope this helps you...
● Explanation -
- Branched chain alkanes have compact shape and weak van der Waals forces.
- Hence, boiling point decreases with increase in branching.
- As 1-bromo butane is straight chain alkane it has quite high boiling point.
- As 2-bromo-2-methyl propane is branched chain alkane its boiling point is lower.
Hope this helps you...
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