Question

Why the H-0-H bond angle is 104.5°, slightly less than the 109.5 of a perfect tetrahedron?​

Answer 1

Answer:

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Explanation:

The H–N–H bond angles in NH3 are slightly smaller than the 109.5° angle in a regular tetrahedron (Figure 3) because the lone pair-bonding pair repulsion is greater than the bonding pair-bonding pair repulsion

Answer 2

Answer:

Regular Tetrahedral molecule such as CH4 has bond angles of 109.5 degrees. However, lone pairs of electrons repel more than bonding pairs, hence the angle between the bonding pairs is reduced to 104.5.

The lone pairs on the oxygen repel the two hydrogen atoms, making the bond angle less than 109.5.the lone pairs around oxygen repel more than bonding pairs, and this means that, for each lone pair, the bond angle is reduced by 2.5o. There are two sets of lone pairs here, so the H-O-H bond angle is 104.5o.