Why the ionization enthalpy of b is less than be
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Explanation:
• as we know that be (berilium) is the element with atomic number 4 and it's atomic configuration is 1s^2 2s^2.
• b(boron) is the element with atomic configuration 1s^2 2s^2 2p^1.
• hence it is easy to take out element in s-block with compare to p-block elements
so ionization enthalpy of b is less than be
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