why the magnetic field at the end of sollenoid is half???
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Now imagine a solenoid in front of you stretching to infinity on both the sides, say from left to right. An infinitely long solenoid has no ends and the field everywhere inside it is same and let its intensity be E. Now cut the solenoid at a point in front of you and throw (!) the half away. You now have in front of you, an end of the remaining half. The field at this end is now due to half the total turns and hence it is E/2.
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