why the unit of potential difference is called derived unit
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To solve this just recall your equations for Electric field strength, which is the force per unit quantity of charge.
E=F/q ……(1)
E=V/d ……(2), implying V=Ed
Now in (1), for consistency of units,
Units of E = units of F/q
1N/C = 1kgm/As^3 (cause 1C= 1As as Q=It)
For consistency between equations (1) and (2),
the units of V/d = the units of F/q
thus, the units of V= units of Fd/q
And finally units of potential difference, 1V = 1 kgm^2/(As^3) read as kilogram meter square per amper seconde cube.
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