why the value of sin 0˙ = 0 ?
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Sin theta = Opposite side / Hypotenuse
for any value of angle theta.
Now if the angle of elevation as theta is 0°.
There will be no length formed opposite the angle.
And even the figure formed will be straight line.
In which the adjacent side and the hypotenuse side will coincide each other
Now as the length of the opposite side will be 0 units and even though there will be some length of the hypotenuse.
The ratio of the opposite side to the hypotenuse will be
Opposite side / Hypotenuse
= 0 / some length of hypo
= 0
Therefore
Sin 0° = 0
Hope you understand this concept soon !!
# Dhruvsh
for any value of angle theta.
Now if the angle of elevation as theta is 0°.
There will be no length formed opposite the angle.
And even the figure formed will be straight line.
In which the adjacent side and the hypotenuse side will coincide each other
Now as the length of the opposite side will be 0 units and even though there will be some length of the hypotenuse.
The ratio of the opposite side to the hypotenuse will be
Opposite side / Hypotenuse
= 0 / some length of hypo
= 0
Therefore
Sin 0° = 0
Hope you understand this concept soon !!
# Dhruvsh
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