Why there is no back bonding in P SiH3 3?
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(B) The back bonding in P(SiH3)3 isn't significant like in N(SiH3)3 bcz P has its 3p orbital (large and not so efficient) whereas N has its 2p orbital, more efficient bonding. (C) Back bonding in N(SiH3)3 so N is sp2 hybridised, hence planar. N(ch3)3 is pyramidal.
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The back bonding in P(SiH3)3 isn't significant like in N(SiH3)3 bcz P has its 3p orbital (large and not so efficient) whereas N has its 2p orbital, more efficient bonding.
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