Why there was SinA/CosA ?
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Answer:
SinA+ CosA
SinA + Sin(π/2-A)
(SinA + SinB= 2Sin((A+B)/2)Cos((A-B)/2))
SinA + Sin(π/2-A)
=2 Sin((A+π/2-A)÷2)Cos((A-π/2+A))÷2)
=2 Sin(π/4)Cos(A-π/4). Sin(π/4)=1/√2
=√2×Cos(A-π/4)
Step-by-step explanation:
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